【codevs4906】删数问题
problemsolutioncodes#include#includeusingnamespacestd;intmain(){intn;strings;cin>>s>>n;for(inti=0;i
problemsolutioncodes#include#includeusingnamespacestd;intmain(){intn;strings;cin>>s>>n;for(inti=0;i
problemsolutioncodes#includeusingnamespacestd;intn,ans=0,c[10],e[10][10];boolok(intpos){for(inti=0;i
problemsolutioncodes#include#include#includeusingnamespacestd;inta[101],b[101];doublef[101][101];intn,m,x,y,s,…
problemsolutioncodes#includeintp[101],a[101],k,n;longlongans[100001],MIN;intmain(){ans[0]=1;scanf("%d%d",&k,&n…
problemsolutioncodes#includeintn,A[15],isp[50],vis[50],ok=1;boolis_prime(intx){for(inti=2;i
problemsolutioncodes#include#include#includeusingnamespacestd;intn,k;doublea[10000];boolC(doublex){intsum=0;fo…
problemsolutioncodes#include#includeusingnamespacestd;intN,M,ans,n;structnm{intPi;intAi;}U[5050];boolcmp(const…
problemsolutioncodes#include#includeusingnamespacestd;structxyz{intx,y;xyz(intx=0,inty=0):x(x),y(y){};};intn,m…
problemsolutioncodes#include#includeusingnamespacestd;intn,m,a[1010][1010],book[1010][1010],x,y,ans;constintdx…
problem给你一个长为n的序列求一个长不超过m的连续子段,使子段和最大solution如果n>m;for(inti=1;i>a[i];s[i]=s[i-1]+a[i];}intl=1,r=1;q[l]=0;//sav…